99x=4.5x^2

Solution for 99x=4.5x^2 equation:

99x=4.5x^2

We move all terms to the left:

99x-(4.5x^2)=0

We get rid of parentheses

-4.5x^2+99x=0

a = -4.5; b = 99; c = 0;
Δ = b2-4ac
Δ = 992-4·(-4.5)·0
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-99}{2*-4.5}=\frac{-198}{-9}
=+22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+99}{2*-4.5}=\frac{0}{-9}
=0
$